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Experimental Physics

JEE Main level, single correct, medium

40 of 70

Question 40 of 70

The vernier scale used for measurement has a positive zero error of $0.2mm.$ If while taking a measurement it was noted that $0$ on the vernier scale lies between $8.5cm$ and $8.6cm$ . Vernier coincidence is $6,$ then the correct value of measurement is $cm.$
(least count $=0.01cm$ )

Show answer and solution

Answer: (B) $8.54cm$

Positive zero error

=0.2mm

Main scale reading

=8.5cm

Vernier scale reading

=6\times 0.01=0.06cm

Final reading

=8.5+0.06-0.02=8.54cm

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