Experimental Physics

JEE Main level, single correct, medium

45 of 70

Question 45 of 70

Using screw gauge of pitch 0.1cm0.1cm and 5050 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as,

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Answer: (B) 2.124cm2.124cm

Thickness =M.S.=M.S. Reading ++ Circular Scale Reading (L.C.)(L.C.)
Here least count is 0.002cmperdivision.0.002cmperdivision.
From all the four options, the second answer is divisible by this least count. Hence option 22 is correct.

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