Experimental Physics

JEE Main level, single correct, medium

52 of 70

Question 52 of 70

The least count of the main scale of a screw gauge is 1mm.1mm. The minimum number of divisions on its circular scale required to measure 5μm5\mu m diameter of a wire is:

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Answer: (D) 200200

Least count of screw gauge =5μm=5 \mu m

L.C=pitchno.ofdivoncirxularscaleL.C=\dfrac{pitch}{no. of div on cirxular scale}

5μm=1mmN5\mu m=\dfrac{1mm}{N}

N=200N=200

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