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Experimental Physics

JEE Main level, single correct, medium

70 of 70

Question 70 of 70

In a Vernier calipers, when both jaws touch each other, zero of the Vernier scale is shifted to the right of zero of the main scale and $7^{\text{th}}$ Vernier division coincides with a main scale reading. If the value of $1$ main scale division is $1$ mm and there are $10$ Vernier scale divisions, then the Vernier caliper has

Show answer and solution

Answer: (C) $0.07$ cm positive zero error

Least count of the Vernier calipers is given by

\text{LC} = \dfrac{1 \text{ MSD}}{\text{Number of VSD}}

.

Substituting the given values,

\text{LC} = \dfrac{1 \text{ mm}}{10} = 0.1 \text{ mm} = 0.01 \text{ cm}

.

Since the zero of the Vernier scale is shifted to the right of the zero of the main scale, the zero error is positive.

The zero error is calculated as

+ (n \times \text{LC})

, where

n

is the coinciding Vernier division.

Given that the

7^{\text{th}}

Vernier division coincides with a main scale reading,

n = 7

.

Zero error

= + (7 \times 0.01 \text{ cm}) = + 0.07 \text{ cm}

.

Therefore, the Vernier caliper has a

0.07 \text{ cm}

positive zero error.

Answer:

0.07

cm positive zero error

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