Gravitation

JEE Main level, single correct, medium

5 of 223

Question 5 of 223

In hydrogen like system the ratio of coul0mbian force and gravitational force between an electron and a proton is in the order of :

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Answer: (A) 103910^{39}

 Fe=kQ1Q2r2=9×109×1.6×10−19×1.6×10−19r2 Fg=Gm1 m2r2=6.67×10−11×9.1×10−31×1.6×10−27r2FeFg≅0.23×1040≅2.3×1039 Option (1) \begin{aligned} & \text { } \mathrm{F}_{\mathrm{e}}=\frac{\mathrm{kQ}_1 \mathrm{Q}_2}{\mathrm{r}^2}=\frac{9 \times 10^9 \times 1.6 \times 10^{-19} \times 1.6 \times 10^{-19}}{\mathrm{r}^2} \\ & \mathrm{~F}_{\mathrm{g}}=\frac{\mathrm{Gm}_1 \mathrm{~m}_2}{\mathrm{r}^2}=\frac{6.67 \times 10^{-11} \times 9.1 \times 10^{-31} \times 1.6 \times 10^{-27}}{\mathrm{r}^2} \\ & \frac{\mathrm{F}_{\mathrm{e}}}{\mathrm{F}_{\mathrm{g}}} \cong 0.23 \times 10^{40} \cong 2.3 \times 10^{39} \\ & \text { Option (1) }\end{aligned}

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