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Kinetic Theory

JEE Main level, single correct, medium

9 of 168

Question 9 of 168

The parameter that remains the same for molecules of all gases at a given temperature is :

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Answer: (A) kinetic energy

From the kinetic interpretation of temperature, we know,

KE=\dfrac{3}{2}{k}_{B}T

. Clearly, it depends only on temperature.

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

Kinetic TheoryThe ratio of specific heats $\gamma = C_p/C_v$ for a rigid diatomic gas molecule is:
Kinetic TheoryThe RMS speed of gas molecules at absolute temperature $T$ is $v_{rms}$ . If the temperature is increased to $4T$ , the new RMS speed is:
Kinetic TheoryOne gas of $n_1$ mole of molecules at temperature $T_1$ , volume $V_1$ , and pressure $P_1$ , and another gas of $n_2$ mole of molecules at temperature $T_2$ , volume $V_2$ , and pressure $P_2$ , are mixed resulting in pressure $P$ and volume $V$ of the mixture. The temperature of the mixture is _____.
Kinetic TheoryA mixture of carbon dioxide and oxygen has volume $8310$ cm $^3$ , temperature $300$ K, pressure $100$ kPa and mass $13.2$ g. The number of moles of carbon dioxide and oxygen gases in the mixture respectively are _______.
(Assume both carbon dioxide and oxygen gases behave like ideal gases) $[R = 8.31$ J/mol.K $]$
Kinetic TheoryThe mean free path of a molecule of diameter $5 \times 10^{-10} \mathrm{~m}$ at the temperature $41^{\circ} \mathrm{C}$ and pressure $1.38 \times 10^{5} \mathrm{~Pa}$ , is given as $\_\_\_\_$ m.
(Given $k_{B}=1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}$ ).
Kinetic TheoryA gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature $50^{\circ} \mathrm{C}$ . The gas is now heated to double its temperature. The modified pressure is $\_\_\_\_$ Pa. Note: Volume is constant.

JEE Main Physics practice question on Kinetic Theory (Gas Laws), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.