Kinetic Theory

JEE Main level, single correct, medium

65 of 168

Question 65 of 168

In the isothermal expansion of 10 g10 \mathrm{~g} of gas from volume V\mathrm{V} to 2 V2 \mathrm{~V} the work done by the gas is 575 J575 \mathrm{~J}.
What is the root mean square speed of the molecules of the gas at that temperature?

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Answer: (C) 499 m/s499 \mathrm{~m} / \mathrm{s}

vrms=3ρv mass of the gas \mathrm{v}_{\mathrm{rms}}=\sqrt{\frac{3 \rho \mathrm{v}}{\text { mass of the gas }}}

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