Kinetic Theory

JEE Main level, single correct, medium

67 of 168

Question 67 of 168

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R
Statement I: Change in internal energy of a system containing
nn mole of ideal gas can be written as ΔU=nCv(Tf−Ti)=nRγ−1(Tf−Ti)\Delta U = n C_v (T_f - T_i) = \dfrac{nR}{\gamma - 1}(T_f - T_i), where γ=CpCv\gamma = \dfrac{C_p}{C_v}, Ti=T_i = initial temperature, Tf=T_f = final temperature.
Statement II: Relation between degree of freedom
ff and γ(=Cp/Cv)\gamma (= C_p/C_v) is (γ=1+2f)\left(\gamma = 1 + \dfrac{2}{f}\right)
Choose the correct answer from the options given below

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Answer: (B) Both A and R are true but R is NOT the correct explanation of A

Statement I is true because for an ideal gas, the change in internal energy is given by ΔU=nCvΔT\Delta U = n C_v \Delta T. Using Mayer's relation Cp−Cv=RC_p - C_v = R and the ratio of specific heats γ=CpCv\gamma = \dfrac{C_p}{C_v}, we can write Cv=Rγ−1C_v = \dfrac{R}{\gamma - 1}. Substituting this, we get ΔU=nRγ−1(Tf−Ti)\Delta U = \dfrac{nR}{\gamma - 1}(T_f - T_i).

Statement II is true because according to the law of equipartition of energy, the molar heat capacity at constant volume is
Cv=f2RC_v = \dfrac{f}{2}R and at constant pressure is Cp=(f2+1)RC_p = \left(\dfrac{f}{2} + 1\right)R. Therefore, γ=CpCv=1+2f\gamma = \dfrac{C_p}{C_v} = 1 + \dfrac{2}{f}.

Statement II does not explain Statement I, as Statement I is derived purely from macroscopic thermodynamic relations (Mayer's relation) and is independent of the microscopic concept of degrees of freedom.


Hence, both statements are true but Statement II is NOT the correct explanation of Statement I.


Answer: Both A and R are true but R is NOT the correct explanation of A

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