Question 72 of 168
The specific heat at constant pressure of a real gas obeying equation is:
Show answer and solution
Answer: (C)
$\begin{aligned}
& \mathrm{dQ}=\mathrm{du}+\mathrm{dW} \\
& \mathrm{CdT}=\mathrm{C}_{\mathrm{V}} \mathrm{dT}+\mathrm{PdV} \\
& \therefore \mathrm{PV}^2=\mathrm{RT} \\
& \mathrm{P}=\text { constant } \\
& \mathrm{P}(2 \mathrm{VdV})=\mathrm{RdT} \\
& \mathrm{PdV}=\frac{\mathrm{RdT}}{2 \mathrm{~V}} \\
&
\end{aligned}$
Put in equation (1)
& \mathrm{dQ}=\mathrm{du}+\mathrm{dW} \\
& \mathrm{CdT}=\mathrm{C}_{\mathrm{V}} \mathrm{dT}+\mathrm{PdV} \\
& \therefore \mathrm{PV}^2=\mathrm{RT} \\
& \mathrm{P}=\text { constant } \\
& \mathrm{P}(2 \mathrm{VdV})=\mathrm{RdT} \\
& \mathrm{PdV}=\frac{\mathrm{RdT}}{2 \mathrm{~V}} \\
&
\end{aligned}$
Put in equation (1)