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Kinetic Theory

JEE Main level, single correct, medium

105 of 168

Question 105 of 168

An ideal gas occupies a volume of $2{m}^{3}$ at a pressure of $3\times {10}^{6}Pa.$ The energy of the gas is:

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Answer: (B) $9\times {10}^{6}J$

V=2{m}^{3}

P=3\times {10}^{6}Pa

PV=nRT

E=\dfrac{f}{2}nRT=\dfrac{f}{2}PV=\dfrac{3}{2}\times 3\times {10}^{6}\times 2

=9\times {10}^{6}J

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

Kinetic TheoryThe ratio of specific heats $\gamma = C_p/C_v$ for a rigid diatomic gas molecule is:
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Kinetic TheoryThe mean free path of a molecule of diameter $5 \times 10^{-10} \mathrm{~m}$ at the temperature $41^{\circ} \mathrm{C}$ and pressure $1.38 \times 10^{5} \mathrm{~Pa}$ , is given as $\_\_\_\_$ m.
(Given $k_{B}=1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}$ ).
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JEE Main Physics practice question on Kinetic Theory (Degree of Freedom and Specific Heat), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

An ideal gas occupies a volume of 2m32{m}^{3}2m3 at a pressure of 3×106Pa.3\times {10}^{6}Pa.3×106Pa. The energy of the gas is:

JEE Main question paper PDF

More Physics practice

An ideal gas occupies a volume of $2{m}^{3}$ at a pressure of $3\times {10}^{6}Pa.$ The energy of the gas is: