Kinetic Theory

JEE Main level, single correct, medium

124 of 168

Question 124 of 168

The helium and argon are put in the flask at the same room temperature ( 300 K). The ratio of average kinetic energies (per molecule) of helium and argon is :
(Give : Molar mass of helium =4 g/mol=4 \mathrm{~g} / \mathrm{mol}, Molar mass of argon =40 g/mol=40 \mathrm{~g} / \mathrm{mol})

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Answer: (D) 1:11: 1

K.E=f2KTK. E=\frac{f}{2} K T
For He and Arf=3\mathrm{Ar} \mathrm{f}=3
K⋅EHe K⋅EAr=11\frac{\mathrm{K} \cdot \mathrm{E}_{\mathrm{He}}}{\mathrm{~K} \cdot \mathrm{E}_{\mathrm{Ar}}}=\frac{1}{1}

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