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Kinetic Theory

JEE Main level, single correct, medium

130 of 168

Question 130 of 168

Two vessels $A$ and $B$ are of the same size and are at same temperature. $A$ contains $1g$ of hydrogen and $B$ contains $1g$ of oxygen. ${P}_{A}$ and ${P}_{B}$ are the pressures of the gases in $A$ and $B$ respectively, then $\dfrac{{P}_{A}}{{P}_{B}}$ is :

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Answer: (A) $16$

For both the gases, it follows that

\dfrac{{P}_{A}{V}_{A}}{{P}_{B}{V}_{B}}=\dfrac{{n}_{A}R{T}_{A}}{{n}_{B}R{T}_{B}}...\left(1\right)

Given

{V}_{A}={V}_{B}

and

{T}_{A}={T}_{B}

.
Thus, from equation (1), it follows that

\begin{matrix}\dfrac{{P}_{A}}{{P}_{B}} & = & \dfrac{{n}_{A}}{{n}_{B}} \\ & = & \dfrac{\dfrac{1}{2}}{\dfrac{1}{32}} \\ & = & 16\end{matrix}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Kinetic Theory (Pressure and Energy of gas), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

Two vessels AAA and BBB are of the same size and are at same temperature. AAA contains 1g1g1g of hydrogen and BBB contains 1g1g1g of oxygen. PA{P}_{A}PA​ and PB{P}_{B}PB​ are the pressures of the gases in AAA and BBB respectively, then PAPB\dfrac{{P}_{A}}{{P}_{B}}PB​PA​​ is :

JEE Main question paper PDF

More Physics practice

Two vessels $A$ and $B$ are of the same size and are at same temperature. $A$ contains $1g$ of hydrogen and $B$ contains $1g$ of oxygen. ${P}_{A}$ and ${P}_{B}$ are the pressures of the gases in $A$ and $B$ respectively, then $\dfrac{{P}_{A}}{{P}_{B}}$ is :