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Kinetic Theory

JEE Main level, single correct, medium

133 of 168

Question 133 of 168

A flask contains Hydrogen and Argon in the ratio $2:1$ by mass. The temperature of the mixture is $30^{\circ}C$ . The ratio of average kinetic energy per molecule of the two gases $\left(\dfrac{{K}_{argon}}{{K}_{hydrogen}}\right)$ is: (Given : Atomic Weight of $Ar=39.9$ )

Show answer and solution

Answer: (B) $1$

The formula to calculate the average kinetic energy per molecule of a gas at any temperature

T

is given by

{K}_{avg}=\dfrac{3}{2}{k}_{B}T

where,

{k}_{B}

is Boltzmann constant.
From above equation, it can be concluded that the average kinetic energy per molecule is independent of the molecular weight of the gas.
Hence, the required ratio is

1:1

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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