Kinetic Theory

JEE Main level, single correct, medium

148 of 168

Question 148 of 168

The volume VV of an enclosure contains a mixture of three gases, 16g16g of oxygen, 28g28g of nitrogen and 44g44g of carbon dioxide at absolute temperature TT. Consider RR as universal gas constant. The pressure of the mixture of gases is :

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Answer: (C) 52RTV\dfrac{5}{2}\dfrac{RT}{V}

PV=(n1+n2+n3)RTPV=\left({n}_{1}+{n}_{2}+{n}_{3}\right)RT
P×V=[1632+2828+4444]RTP\times V=\left[\dfrac{16}{32}+\dfrac{28}{28}+\dfrac{44}{44}\right]RT
PV=[12+1+1]RTPV=\left[\dfrac{1}{2}+1+1\right]RT
P=52RTVP=\dfrac{5}{2}\dfrac{RT}{V}

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