Kinetic Theory

JEE Main level, numerical answer, medium

152 of 168

Question 152 of 168

A closed vessel contains 0.10.1 mole of a monoatomic ideal gas at 200K200\text{K}. If 0.050.05 mole of the same gas at 400K400K is added to it, the final equilibrium temperature (in K\text{K}) of the gas in the vessel will be close to ______

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Answer: 267

(0.1)(200)+(0.05)(400)=(0.15)T\left(0.1\right)\left(200\right)+\left(0.05\right)\left(400\right)=\left(0.15\right)TT=20+200.15=8003=266.67T=\dfrac{20+20}{0.15}=\dfrac{800}{3}=266.67
=266.67=266.67

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