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Laws of Motion

JEE Main level, single correct, medium

39 of 210

Question 39 of 210

Two masses $A$ and $B$ , each of mass $M$ are fixed together by a massless spring, A force acts on the mass $B$ as shown in figure. If the mass $A$ starts moving away from mass $B$ with acceleration $a$ , then the acceleration of mass $B$ will be :

Show answer and solution

Answer: (D) $\dfrac{F-Ma}{M}$

{a}_{cm}=\dfrac{{m}_{1}{a}_{1}+{m}_{2}{a}_{2}}{{m}_{1}+{m}_{2}}

\dfrac{F}{2M}=\dfrac{Ma+M{a}_{B}}{2M}

{a}_{B}=\dfrac{F-Ma}{M}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Laws of Motion (Newton's laws of motion), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

Two masses AAA and BBB, each of mass MMM are fixed together by a massless spring, A force acts on the mass BBB as shown in figure. If the mass AAA starts moving away from mass BBB with acceleration aaa, then the acceleration of mass BBB will be :

JEE Main question paper PDF

More Physics practice

Two masses $A$ and $B$ , each of mass $M$ are fixed together by a massless spring, A force acts on the mass $B$ as shown in figure. If the mass $A$ starts moving away from mass $B$ with acceleration $a$ , then the acceleration of mass $B$ will be :