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Laws of Motion

JEE Main level, single correct, medium

70 of 210

Question 70 of 210

Three identical blocks of masses $\mathrm{m}=2 \mathrm{~kg}$ are drawn by a force $\mathrm{F}=10.2 \mathrm{~N}$ with an acceleration of $0.6 \mathrm{~ms}^{-2}$ on a frictions surface, then what is the tension (in $\mathrm{N}$ ) in the string between the blocks $B$ and $C$ ?

Show answer and solution

Answer: (B) 7.8

Apply Newton's second law

\mathrm{F}-\mathrm{T}_{\mathrm{ab}}=m a ; \mathrm{T}_{\mathrm{ab}}-\mathrm{T}_{\mathrm{bc}}=\mathrm{ma} \quad \therefore \mathrm{T}_{\mathrm{bc}}=7.8 \mathrm{~N}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Laws of Motion (Newton's laws of motion), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.