Laws of Motion

JEE Main level, single correct, medium

79 of 210

Question 79 of 210

A body of weight 200 N200 \mathrm{~N} is suspended from a tree branch through a chain of mass 10 kg10 \mathrm{~kg}. The branch pulls the chain by a force equal to (if g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^2 ) :

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Answer: (C) 300 N300 \mathrm{~N}


Chain block system is in equilibrium so

T=200+100=300 N. \mathrm{T}=200+100=300 \mathrm{~N} \text {. }

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