Question 98 of 210

A car is moving on a plane inclined at $30^{\circ}$ to the horizontal with an acceleration of $10{ms}^{-2}$ parallel to the plane upward. A bob is suspended by a string from the roof of the car. The angle in degrees which the string makes with the vertical is (Take $g=10{ms}^{-2}$)

Your answerCheck answer

Show answer and solution▾

Answer: 30

First, make the free body diagram, of an inclined plane with acceleration in an inclined plane moving in an upward direction.

With respect to the car, the F.B.D. is as follows at equilibrium, $T$ is equal and opposite to the resultant of ${a}_{1}$ ​ and ${a}_{2}$ ​ As ${a}_{1}+{a}_{2}$ ​ makes $30^{\circ}$with vertical; $T$ and, the string is also making $30^{\circ}$ with vertical.