Question 102 of 210

A mass of $10kg$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of $45^{\circ}$ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is $\left(g=10m{s}^{-2}\right)$

A$100N$B$200N$C$140N$D$70N$

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Answer: (A) $100N$

$T\cos ⁡45^{\circ}=mg$

$T\sin ⁡45^{\circ}=F$

$tan45^{\circ}=\dfrac{F}{mg}$

$F=mg=100N$