Laws of Motion

JEE Main level, single correct, medium

132 of 210

Question 132 of 210

A block is sliding down on an inclined plane of slope θ\theta and at an instant t=0t=0 this block is given an upward momentum so that it starts moving up on the inclined surface with velocity uu. The distance (S)(S) travelled by the block before its velocity become zero, is ____\_\_\_\_.
(g=g= gravitational acceleration)

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Answer: (B) u22gsin⁡θ\frac{u^{2}}{2 g \sin \theta}

a=−gsin⁡θa = -g\sin\theta
V2=U2+2asV^2 = U^2 + 2as
0=u2−2gsin⁡θ⋅s0 = u^2 - 2g\sin\theta \cdot s
s=u22gsin⁡θs = \dfrac{u^2}{2g\sin\theta}

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