Laws of Motion

JEE Main level, single correct, medium

136 of 210

Question 136 of 210

A heavy box of mass 50 kg50 \mathrm{~kg} is moving on a horizontal surface. If co-efficient of kinetic friction between the box and horizontal surface is 0.3 then force of kinetic friction is :

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Answer: (B) 147 N147 \mathrm{~N}


Fk=μkN=0.3×50×9.8=147NF_k=\mu_k N=0.3 \times 50 \times 9.8=147 N

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