Laws of Motion

JEE Main level, numerical answer, medium

158 of 210

Question 158 of 210

The coefficient of static friction between two blocks is 0.50.5 and the table is smooth. The maximum horizontal force that can be applied to move the blocks together is _______NN (take g=10ms−2)\left.g=10{ms}^{-2}\right)

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Answer: 15

For Fmax⁡{F}_{\max } with relative rest, fs{f}_{s} between
2kg&1kg must be maximum.

Acommon≤amax⁡{A}_{common}\leq {a}_{\max }
F3≤102\dfrac{F}{3}\leq \dfrac{10}{2}
F≤15F\leq 15

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