Laws of Motion

JEE Main level, single correct, medium

176 of 210

Question 176 of 210

A body of mass 2 kg2 \mathrm{~kg} slides down with an acceleration of 3 m/s23 \mathrm{~m} / \mathrm{s}^2 on a rough inclined plane having a slope of 30∘30^{\circ}. The external force required to take the same body up the plane with the same acceleration will be: (g=10 m/s2)\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)

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Answer: (D) 20 N20 \mathrm{~N}

Equation of motion when the mass slides down
Mgsin⁡θ−f=Ma⇒10−f=6(M=2 kg,a=3 m/s2,θ=30∘ given )∴f=4 N\begin{aligned} &M g \sin \theta-f=M a \\ &\Rightarrow 10-f=6 \\ &\quad\left(M=2 \mathrm{~kg}, a=3 \mathrm{~m} / \mathrm{s}^2, \theta=30^{\circ} \text { given }\right) \\ &\therefore f=4 \mathrm{~N} \end{aligned}
{ Equation of motion when the block is }

pushed up

Let the external force required to take the block up the plane with same acceleration be
FF
F−Mgsin⁡θ−f=Ma⇒F−10−4=6F=20 N\begin{aligned} &F-M g \sin \theta-f=M a \\ &\Rightarrow F-10-4=6 \\ &F=20 \mathrm{~N} \end{aligned}

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