Laws of Motion

JEE Main level, single correct, medium

180 of 210

Question 180 of 210

A rocket is fired vertically from the earth with an acceleration of 2g, where g is the gravitational acceleration. On an inclined plane inside the rocket, making an angle θ\theta with the horizontal, a point object of mass m is kept. The minimum coefficient of friction μmin{\mu }_{min} between the mass and the inclined surface such that the mass does not move is:

Show answer and solution

Answer: (B) tan⁡⁡θ\tan ⁡\theta



3mgsin⁡⁡θ=μ3mgcos⁡⁡θ3mg\sin ⁡\theta =\mu 3mg\cos ⁡\theta

μ=tan⁡⁡θ\mu =\tan ⁡\theta

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Laws of motion, friction and pulleys simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Laws of Motion (Frictional force), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.