Laws of Motion

JEE Main level, single correct, medium

196 of 210

Question 196 of 210

The minimum velocity (in ms−1\mathrm{ms}^{-1} ) with which a car driver must traverse a flat curve of radius 150 m150 \mathrm{~m} and coefficient of friction 0.60.6 to avoid skidding is

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Answer: (B) 30

The condition to avoid skidding, v=μrg=0.6×150×10=30 m/s\mathrm{v}=\sqrt{\mu \mathrm{rg}}=\sqrt{0.6 \times 150 \times 10}=30 \mathrm{~m} / \mathrm{s}

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