Laws of Motion

JEE Main level, single correct, medium

201 of 210

Question 201 of 210

A car is moving on a horizontal curved road with radius 50m50m. The approximate maximum speed of car will be, if friction between tyres and road is 0.340.34. [Take g=10ms−2g=10m{s}^{-2}]

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Answer: (C) 13ms−113m{s}^{-1}

For a car moving with uniform speed along a circular track, the centripetal acceleration is provided by the frictional force acting radially inwards. Therefore, applying Newton's second law along radial direction,
μmg=mv2r\mu mg=\dfrac{m{v}^{2}}{r}
⇒v=μrg\Rightarrow v=\sqrt{\mu rg}
=0.34×50×10=\sqrt{0.34\times 50\times 10}
≈13ms−1\approx 13m{s}^{-1}

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