Doubtclip is an AI tutor that turns any homework or exam doubt into a step-by-step whiteboard video lesson with diagrams, formulas, and voice explanation.

Which subjects and exams does it support?

It supports Physics, Chemistry, Mathematics/Calculus and related STEM doubts for school boards, JEE, NEET, and global high-school / undergrad practice.

How do I get a video solution?

Upload a photo of the question or paste the text, sign in, and Doubtclip generates a whiteboard-style explanation video you can watch and share.

Is Doubtclip available worldwide?

Yes. Doubtclip is a web app for students globally. Lessons are available in English and Hinglish.

Mechanical Properties of Solids

JEE Main level, single correct, medium

8 of 118

Question 8 of 118

Figure represents the extension ( $\Delta l$ ) of a wire of length $1$ meter, suspended from the ceiling of the room at one end with a load $W$ connected to the other end. If the cross-sectional area of the wire is $10^{-5}$ m $^2$ then the Young's modulus of the wire is __________ N/m $^2$ .

Show answer and solution

Answer: (C) $1.0 \times 10^{10}$

From the given graph, we can observe that for a load

W = 20

N, the extension is

\Delta l = 2 \times 10^{-4}

m.

The formula for Young's modulus

Y

is:

Y = \dfrac{\text{Stress}}{\text{Strain}} = \dfrac{W / A}{\Delta l / L} = \dfrac{W L}{A \Delta l}

Given:
Length of the wire,

L = 1

m
Cross-sectional area,

A = 10^{-5}

^2

Substituting the values into the formula:

Y = \dfrac{20 \times 1}{10^{-5} \times 2 \times 10^{-4}}

Y = \dfrac{20}{2 \times 10^{-9}}

Y = 10 \times 10^9 = 1.0 \times 10^{10}

N/m

^2

Answer:

1.0 \times 10^{10}

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

See it move: Elasticity: stress, strain and Young’s modulus simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Mechanical Properties of Solids (Young’s Modulus and Breaking Stres), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.