Mechanical Properties of Solids

JEE Main level, single correct, medium

21 of 118

Question 21 of 118

Match List-I with List-II :
$\begin{array}{|c|c|c|c|}

\hline & \text { List-I } & & \text { List-II } \\

\hline \text { (A) } & \text { A force that restores an elastic body of unit area to its original state } & \text { (I) } & \text { Bulk modulus } \\

\hline \text { (B) } & \text { Two equal and opposite forces parallel to opposite faces } & \text { (II) } & \text { Young's modulus } \\

\hline \text { (C) } & \begin{array}{l}

\text { Forces perpendicular everywhere to the surface per unit area } \\

\text { same everywhere }

\end{array} & \text { (III) } & \text { Stress } \\

\hline \text { (D) } & \text { Two equal and opposite forces perpendicular to opposite faces } & \text { (IV) } & \text { Shear modulus } \\

\hline

\end{array}$

Choose the correct answer from the options given below :

Show answer and solution

Answer: (B) (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(1) stress =Frestoring A=\frac{F_{\text {restoring }}}{A}
If
A=1\mathrm{A}=1
Stress
=Frestoring =F_{\text {restoring }}
(A)-(III)

(2)

(B)-(IV)

(3)

(C)-(I)

(4)

(D)-(II)

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