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Mechanical Properties of Solids

JEE Main level, single correct, medium

54 of 118

Question 54 of 118

A uniform heavy rod of weight $10kg{ms}^{-2},$ cross-sectional area $100{cm}^{2}$ and length $20cm$ is hanging from a fixed support. Young modulus of the material of the rod is $2\times {10}^{11}N{m}^{-2}.$ Neglecting the lateral contraction, find the elongation of rod due to its own weight:

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Answer: (A) $5\times {10}^{-10}m$

Elongation due to self weight,

\dfrac{Wl}{2AY}=\dfrac{10\times 0.2}{2\times 2\times {10}^{11}\times 100\times {10}^{-4}}=5\times {10}^{-10}m

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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