Mechanical Properties of Solids

JEE Main level, numerical answer, medium

88 of 118

Question 88 of 118

The volume contraction of a solid copper cube of edge length 10 cm , when subjected to a hydraulic pressure of 7×106 Pa7 \times 10^6 \mathrm{~Pa}, would be ____ mm3\mathrm{mm}^3.
(Given bulk modulus of copper =1.4×1011 N m−2=1.4 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2} )

Show answer and solution

Answer: 50

B=ΔPΔVVΔV=7×1061.4×1011×(10×10−2)3Δ V=50 mm3\begin{aligned} & \mathrm{B}=\frac{\Delta \mathrm{P}}{\frac{\Delta \mathrm{V}}{\mathrm{V}}} \\ & \Delta \mathrm{V}=\frac{7 \times 10^6}{1.4 \times 10^{11}} \times\left(10 \times 10^{-2}\right)^3 \\ & \Delta \mathrm{~V}=50 \mathrm{~mm}^3\end{aligned}

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Elasticity: stress, strain and Young’s modulus simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Mechanical Properties of Solids (Bulk Modulus), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.