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Mechanical Properties of Solids

JEE Main level, single correct, medium

97 of 118

Question 97 of 118

An object is located at $2km$ beneath the surface of the water. If the fractional compression $\dfrac{\Delta V}{V}$ is $1.36%$ , the ratio of hydraulic stress to the corresponding hydraulic strain will be ______[Given: density of water is $1000kg{m}^{-3}$ and $g=9.8{ms}^{-2}.$

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Answer: (D) $1.44\times {10}^{9}N{m}^{-2}$

P=h\rho g

\beta =\dfrac{p}{\dfrac{\Delta V}{V}}=\dfrac{2\times {10}^{3}\times {10}^{3}\times 9.8}{1.36\times {10}^{-2}}

=1.44\times {10}^{9}N{m}^{-2}

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JEE Main 2025 Apr 2 Shift 1 question paper

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