Mechanical Properties of Solids

JEE Main level, single correct, medium

104 of 118

Question 104 of 118

A cylindrical rod of length 1 m and radius 4 cm is mounted vertically. It is subjected to a shear force of 105 N10^5 \mathrm{~N} at the top. Considering infinitesimally small displacement in the upper edge, the angular displacement θ\theta of the rod axis from its original position would be : (shear moduli, G=1010 N/m2)\left.\mathrm{G}=10^{10} \mathrm{~N} / \mathrm{m}^2\right)

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Answer: (A) 1/160π1 / 160 \pi


 Shear moduli =σshear θ1010=105π×16×10−4×1θθ=1160π Radian \begin{aligned} & \text { Shear moduli }=\frac{\sigma_{\text {shear }}}{\theta} \\ & 10^{10}=\frac{10^5}{\pi \times 16 \times 10^{-4}} \times \frac{1}{\theta} \\ & \theta=\frac{1}{160 \pi} \text { Radian }\end{aligned}

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