Question 148 of 308

A car is standing $200m$ behind a bus, which is also at rest. The two start moving at the same instant but with different forward accelerations. The bus has acceleration $2m{s}^{-2}$ and the car has acceleration $4m{s}^{-2}$ . The car will catch up with the bus after time :

A$\sqrt{120}\text{s}$B$15\text{s}$C$\sqrt{110}\text{s}$D$10\sqrt{2}\text{s}$

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Answer: (D) $10\sqrt{2}\text{s}$

${a}_{CB}=2m{\sec }^{-2}$

$200=\dfrac{1}{2}\times 2{t}^{2}$

$t=10\sqrt{2}s$