Kinematics

JEE Main level, single correct, medium

149 of 308

Question 149 of 308

A person climbs up a stalled escalator in 60 s60 \mathrm{~s}. If standing on the same but escalator running with constant velocity he takes 40 s40 \mathrm{~s}. How much time is taken by the person to walk up the moving escalator?

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Answer: (C) 24 s24 \mathrm{~s}

Person's speed walking only is 160 "escalator"  second \frac{1}{60} \frac{\text { "escalator" }}{\text { second }}
Standing the escalator without walking the
speed is 140 "escalator"  second \frac{1}{40} \frac{\text { "escalator" }}{\text { second }}
Walking with the escalator going, the speed add.
So, the person's speed is 160+140=15120\frac{1}{60}+\frac{1}{40}=\frac{15}{120}
 "escalator"  second \frac{\text { "escalator" }}{\text { second }}
So, the time to go up the escalator ("seconds per escalator") is

t=1205=24 second t=\frac{120}{5}=24 \text { second }

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