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Kinematics

JEE Main level, single correct, medium

270 of 308

Question 270 of 308

A projectile is given an initial velocity of $\left(\hat{i}+2\hat{j}\right)m{s}^{-1}$ , where $\hat{\text{i}}$ is along the ground and $\hat{\text{j}}$ is along the vertical upward. If $g=10m{s}^{-2}$ , the equation of its trajectory is :

Show answer and solution

Answer: (D) $y=2x-5{x}^{2}$

\vec{\text{v}}=\hat{\text{i}}+2\hat{\text{j}}

\Rightarrow \text{x}=\text{t}

..... (i)

\text{y}=2\text{t}-\dfrac{1}{2}\left(10{\text{t}}^{2}\right)

..... (ii)

From (i) and (ii)

\text{y}=2\text{x}-5{\text{x}}^{2}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Kinematics (Projectile motion), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

A projectile is given an initial velocity of (i^+2j^)ms−1\left(\hat{i}+2\hat{j}\right)m{s}^{-1}(i^+2j^​)ms−1, where i^\hat{\text{i}}i^ is along the ground and j^\hat{\text{j}}j^​ is along the vertical upward. If g=10ms−2g=10m{s}^{-2}g=10ms−2, the equation of its trajectory is :

JEE Main question paper PDF

More Physics practice

A projectile is given an initial velocity of $\left(\hat{i}+2\hat{j}\right)m{s}^{-1}$ , where $\hat{\text{i}}$ is along the ground and $\hat{\text{j}}$ is along the vertical upward. If $g=10m{s}^{-2}$ , the equation of its trajectory is :