Kinematics

JEE Main level, single correct, medium

299 of 308

Question 299 of 308

A modern grand-prix racing car of mass mm is travelling on a flat track in a circular arc of radius RR with a speed v.v. If the coefficient of static friction between the tyres and the track is μs,{\mu }_{s}, then the magnitude of negative lift FL{F}_{L} acting downwards on the car is:

Show answer and solution

Answer: (B) m(v2μsR−g)m\left(\dfrac{{v}^{2}}{{\mu }_{s}R}-g\right)

μsN=mv2R{\mu }_{s}N=\dfrac{m{v}^{2}}{R}
N=mv2μsR=mg+FLN=\dfrac{m{v}^{2}}{{\mu }_{s}R}=mg+{F}_{L}
FL=mv2μsR−mg{F}_{L}=\dfrac{m{v}^{2}}{{\mu }_{s}R}-mg

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Projectile motion simulationDrag the sliders and watch the numbers in this question change.Revise Kinematics & Projectile Motion firstFormula sheet, solved examples and the traps students fall into.

More Physics practice

JEE Main Physics practice question on Kinematics (Uniform Circular Motion), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.