Kinematics

JEE Main level, single correct, medium

300 of 308

Question 300 of 308

A block of 200g200g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20cm20cm. If the block takes 40s40s to complete one round, the normal force by the side walls of the groove is:

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Answer: (D) 9.859×10−4N9.859\times {10}^{-4}N

N=mω2RN=m{\omega }^{2}R
Given m=0.2kg,T=40S,R=0.2mm=0.2kg,T=40S,R=0.2m
Put values in equation (1)\left(1\right)
N=9.859×10−4NN=9.859\times {10}^{-4}N

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