Atoms & Nuclei

JEE Main level, single correct, medium

158 of 239

Question 158 of 239

An atom 38X{ }_{3}^{8} X is bombarded by shower of fundamental particles and in 10 s this atom absorbed 10 electrons, 10 protons and 9 neutrons. The percentage growth in the surface area of the nucleons is recorded by:

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Answer: (D) 125%125 \%

Surface area x∝A2/3x \propto A^{2/3}
Xi=82/3K=4KX_i = 8^{2/3} K = 4K
Xf=(8+10+9)2/3K=9KX_f = (8 + 10 + 9)^{2/3} K = 9K
% increase in surface area of nucleus
xi=9K−4K4K×100=125%x_i = \dfrac{9K - 4K}{4K} \times 100 = 125\%

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