Atoms & Nuclei

JEE Main level, single correct, medium

209 of 239

Question 209 of 239

Assume that a neutron breaks into a proton and an electron. The energy released during this process is (Mass of neutron =1.6725×10−27 kg;=1.6725 \times 10^{-27} \mathrm{~kg} ; mass of proton =1.6725×10−27 kg;=1.6725 \times 10^{-27} \mathrm{~kg} ; mass of electron =9×10−31=9 \times 10^{-31} kg)\mathrm{kg})

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Answer: (A) 0.73 MeV0.73 \mathrm{~MeV}

$\begin{aligned}
\Delta m & =\left(m_p+m_e\right)-m_n \\

& =9 \times 10^{-31} \mathrm{~kg}.

\end{aligned}$

Energy released
=(9×10−31 kg)c2=\left(9 \times 10^{-31} \mathrm{~kg}\right) \mathrm{c}^2 joules
$\begin{aligned}

& =\frac{9 \times 10^{-31} \times\left(3 \times 10^8\right)^2}{1.6 \times 10^{-13}} \mathrm{MeV} \\

& =0.73 \mathrm{~MeV} .

\end{aligned}$

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