Atoms & Nuclei

JEE Main level, single correct, medium

219 of 239

Question 219 of 239

In a hypothetical fission reaction
92X236→56Y141+36Z92+3R{ }_{92} X^{236} \rightarrow{ }_{56} Y^{141}+{ }_{36} Z^{92}+3 R
The identity of emitted particles ( R)\mathrm{R}) is :

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Answer: (B) Neutron

$\begin{aligned}
& \mathrm{Z} \text { in LHS }=92 \\
& \mathrm{Z} \text { in } \mathrm{RHS}=56+36=92 \\
& \mathrm{~A} \text { in } \mathrm{LHS}=236 \\
& \mathrm{~A} \text { in } \mathrm{RHS}=141+92=233
\end{aligned}$
So 3 neutrons are released.

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