Rotational Motion

JEE Main level, single correct, medium

122 of 280

Question 122 of 280

Shown in the figure is rigid and uniform one meter long rod ABAB held in horizontal position by two strings tied to its ends and attached to the ceiling. The rod is off mass ′m′'m' and has another weight of mass 2m2m hung at a distance of 75cm75cm from AA. The tension in the string at AA is:

Show answer and solution

Answer: (D) 1mg1mg

Net torque(τnet)\left({\tau }_{net}\right) aboutBB is zero at equilibrium

TA×100−mg×50−2mg×25=0{T}_{A}\times 100-mg\times 50-2mg\times 25=0
TA×100=100×mg{T}_{A}\times 100=100\times mg
∴TA=1mg∴{T}_{A}=1mg.

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Rotational dynamics and rolling simulationDrag the sliders and watch the numbers in this question change.Revise Rotational Motion firstFormula sheet, solved examples and the traps students fall into.

More Physics practice

JEE Main Physics practice question on Rotational Motion (Torque), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.