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Thermal Properties of Matter

JEE Main level, single correct, medium

71 of 126

Question 71 of 126

A calorimeter of water equivalent $20g$ contains $180g$ of water at $25^{\circ}C$ . $m''$ ' grams of steam at $100^{\circ}C$ is mixed in it till the temperature of the mixture is $31^{\circ}C$ . The value of $m''$ is close to (Latent heat of water $=540cal{g}^{-1}$ , specific heat of water $=1cal{g}^{-1^{\circ}}{C}^{-1}$ )

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Answer: (A) $2$

\left(200\right)\left(31-25\right)=m\times 540+m\left(1\right)\left(69\right)

1200=m\left(609\right)

m\approx 2

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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