Question 78 of 126
Ice at is added to of water at , When the temperature of the mixture reaches it is found that 20 of ice is still unmelted. The amount of ice added to the
water was close to (Specific heat of water
Specific heat of Ice
Heat of fusion of water at
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Answer: (D)
Let m gram of ice is added. From principal of calorimeter heat gained (by ice) heat lost (by water)
$\begin{array}{l}
\therefore 20 \times 2.1 \times \mathrm{m}+(\mathrm{m}-20) \times 334 \\
=50 \times 4.2 \times 40 \\
376 \mathrm{~m}=8400+6680 \\
\mathrm{~m}=40.1
\end{array}$
$\begin{array}{l}
\therefore 20 \times 2.1 \times \mathrm{m}+(\mathrm{m}-20) \times 334 \\
=50 \times 4.2 \times 40 \\
376 \mathrm{~m}=8400+6680 \\
\mathrm{~m}=40.1
\end{array}$