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Thermal Properties of Matter

JEE Main level, single correct, medium

86 of 126

Question 86 of 126

$100 \mathrm{~g}$ of water is heated from $30^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ . Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is $4148 \mathrm{~J} / \mathrm{kg} / \mathrm{K}$ ):

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Answer: (A) $8.4 \mathrm{~kJ}$

\Delta \mathrm{Q}=\Delta \mathrm{U}+\Delta \mathrm{W}

(ignoring expansion)

\Delta \mathrm{U}=\mathrm{ms} \Delta \mathrm{T}=0.1 \times 4.184 \times 20=8.368 \mathrm{~kJ}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Thermal Properties of Matter (Calorimetry), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

100 g100 \mathrm{~g}100 g of water is heated from 30∘C30^{\circ} \mathrm{C}30∘C to 50∘C50^{\circ} \mathrm{C}50∘C. Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is 4148 J/kg/K4148 \mathrm{~J} / \mathrm{kg} / \mathrm{K}4148 J/kg/K ):

JEE Main question paper PDF

More Physics practice

$100 \mathrm{~g}$ of water is heated from $30^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ . Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is $4148 \mathrm{~J} / \mathrm{kg} / \mathrm{K}$ ):