Thermal Properties of Matter

JEE Main level, single correct, medium

113 of 126

Question 113 of 126

The temperature of two outer surfaces of a composite slab, consisting of two materials having coefficients of thermal conductivity KK and 2K2 K and thickness xx and 4x4 x, respectively are T2T_2 and T1(T2>T1)T_1\left(T_2\gt T_1\right). The rate of heat transfer through the slab, in a steady state is (A(T2−T1)Kx)f\left(\frac{A\left(T_2-T_1\right) K}{x}\right) f, with ff equal to

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Answer: (D) 1/31 / 3

Δq=kAx[T2−2 T2−T13]\Delta \mathrm{q}=\frac{\mathrm{kA}}{\mathrm{x}}\left[\mathrm{T}_2-\frac{2 \mathrm{~T}_2-\mathrm{T}_1}{3}\right]
=kA3x[T2−T1]=\frac{\mathrm{kA}}{3 \mathrm{x}}\left[\mathrm{T}_2-\mathrm{T}_1\right]

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