Thermal Properties of Matter

JEE Main level, single correct, medium

121 of 126

Question 121 of 126

The heat radiated per unit area in 1 hour by a furnace whose temperature is 3000 K3000 \mathrm{~K} is (σ=5.7×(\sigma=5.7 \times 10−8 W m−2 K−410^{-8} \mathrm{~W} \mathrm{~m}^{-2} \mathrm{~K}^{-4} )

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Answer: (A) 1.7×1010 J1.7 \times 10^{10} \mathrm{~J}

According to Stefan's law
E=σT4E=\sigma T^4
Heat radiated per unit area in 1 hour ( 3600 s)3600 \mathrm{~s}) is
=5.7×10−8×(300)4×3600=1.7×1010 J=5.7 \times 10^{-8} \times(300)^4 \times 3600=1.7 \times 10^{10} \mathrm{~J}

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