Question 24 of 190
The internal energy of air in sized room at 1 atmospheric pressure will be _______ . (Consider air as diatomic molecule)
Show answer and solution
Answer: 12
To find the internal energy of gas in the room.
$\begin{aligned}
& \mathrm{U}=\mathrm{nC}_{\mathrm{v}} \mathrm{~T}=\mathrm{n} \frac{5 \mathrm{RT}}{2} \\
& =\frac{5}{2} \mathrm{PV}=\frac{5}{2} \times 10^5 \times 48=12 \times 10^6 \mathrm{~J}
\end{aligned}$
$\begin{aligned}
& \mathrm{U}=\mathrm{nC}_{\mathrm{v}} \mathrm{~T}=\mathrm{n} \frac{5 \mathrm{RT}}{2} \\
& =\frac{5}{2} \mathrm{PV}=\frac{5}{2} \times 10^5 \times 48=12 \times 10^6 \mathrm{~J}
\end{aligned}$