Units & Dimensions

JEE Main level, single correct, medium

13 of 149

Question 13 of 149

If EE and HH represents the intensity of electric field and magnetizing field respectively, then the unit of EH\dfrac{E}{H} will be:

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Answer: (B) ohm

The unit of, EH=FqIr=FrI2t,\dfrac{E}{H}=\dfrac{\dfrac{F}{q}}{\dfrac{I}{r}}=\dfrac{Fr}{{I}^{2}t}, here the units are, F=NF=N, r=mr=m, I=AI=A and t=st=s then the net unit of EH\dfrac{E}{H},is J s−1A−2{\text{J s}}^{-1}{\text{A}}^{-2}, which is equivalent to Ω\Omega.

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