Units & Dimensions

JEE Main level, single correct, medium

30 of 149

Question 30 of 149

Match List-I with List-II.
List-IList-II(A)Mass density(I)[ML2 T−3](B)Impulse(II)[MLT−1](C)Power(III)[ML2 T0](D)Moment of inertia(IV)[ML−3 T0]\begin{array}{|l|l|l|l|} \hline & \text{List-I} & & \text{List-II} \\ \hline \text{(A)} & \text{Mass density} & \text{(I)} & {\left[\mathrm{ML}^2 \mathrm{~T}^{-3}\right]} \\ \hline \text{(B)} & \text{Impulse} & \text{(II)} & {\left[\mathrm{MLT}^{-1}\right]} \\ \hline \text{(C)} & \text{Power} & \text{(III)} & {\left[\mathrm{ML}^2 \mathrm{~T}^0\right]} \\ \hline \text{(D)} & \text{Moment of inertia} & \text{(IV)} & {\left[\mathrm{ML}^{-3} \mathrm{~T}^0\right]} \\ \hline\end{array}
Choose the correct answer from the options given below :

Show answer and solution

Answer: (C) (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

(A) Mass density =MV=M1L−3=\frac{M}{V}=M^1 L^{-3}...(iv)
(B) Impulse
=M×u=M1 L1 T−1=\mathrm{M} \times \mathrm{u}=\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-1}....(ii)
(C) Power
=F.V=M1 L2 T−3=\mathrm{F}. \mathrm{V}=\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-3}....(i)
(D) Moment of inertia
=Mr2=M1 L2=\mathrm{Mr}^2=\mathrm{M}^1 \mathrm{~L}^2...(iii)

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

More Physics practice

JEE Main Physics practice question on Units & Dimensions (Dimensions), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.